Solution one task of Boolean Algebra via Python module utilizing **dict(zip([keys],[values]))

The approach of utilizing **dict(zip([keys],[values])) for solving a wide range of tasks in the course of Boolean Algebra for students is known in general . This post is just a demo of flexibility of python programming for a hard to complete similar tasks in the way limited by the framework of exclusively truth tables, even obtained with limited Python programming skills

The logical function F is given by the expression:

A partially filled fragment containing non-repeating rows of the

truth table of function F is given. Determine which column of the

truth table corresponds to each of the variables x, y, z, w

In your answer, write the letters w,x,y,z in the order in which the

columns corresponding to them appear ( first the letter corresponding to the first column; then the letter corresponding to the second column, etc.) . Write the letters in your answer in a row; no separators need to be placed between the letters.

Solution of the problem above

Instead of building truth table for x,y,z,w via nested loop :-

print("x y z w")
for x in  range(0,2):
      for y in range(0,2):
         for z in range(0,2):
             for w in range(0,2):
                 if ((w == y) or (((not x) <= z) and ((not z) <= y))) == 0:
                             print(x, y, z, w)

and attempt to place x,y,z,w as correct headers of original columns of the table above using Boolean reasoning .

We intend to run python module below

 ─boris ~/DICTZIP02

╰─ ❯❯ cat djs02-dzen.py

def f(x, y, w, z):

    # due to (not(x) -> z) is equivalent (x or z)

    # due to (not(z) -> y) is equivalent (z or y)

    return (w == y) or ((x or z) and (z or y))

from itertools import *

for a1, a2, a3, a4, a5, a6, a7, a8 in product([0, 1], repeat=8):

    t = [(a1,1,1,a2), (a3,a4,1,a5),(1,a6,a7,a8)]

    if len(set(t)) == 3:

        for p in permutations('xywz'):

            if [f(**dict(zip(p, r))) for r in t] == [0, 0, 0]:

                print(*p, sep='')

and obtain result in a few minutes

 ─boris~/DICTZIP02

╰─ ❯❯ python djs02-dzen.py

yxwz

References

1. https://stackoverflow.com/questions/209840/make-a-dictionary-dict-from-separate-lists-of-keys-and-values

2.  https://stackoverflow.com/questions/21809112/what-does-tuple-and-dict-mean-in-python

**d means "treat the key-value pairs in the dictionary as additional named arguments to this function call."

def foo(x, y):

    print(x, y)

>>> d = {'x':1, 'y':2}

>>> foo(**d)

1 2